(6x^2+5x+10)-(4x^2+6x+12=)

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Solution for (6x^2+5x+10)-(4x^2+6x+12=) equation: 



(6x^2+5x+10)-(4x^2+6x+12=)

We move all terms to the left:

(6x^2+5x+10)-(4x^2+6x+12-())=0

We get rid of parentheses

6x^2+5x-(4x^2+6x+12-())+10=0



We calculate terms in parentheses: -(4x^2+6x+12-()), so:

4x^2+6x+12-()

We add all the numbers together, and all the variables

4x^2+6x

Back to the equation:

-(4x^2+6x)



We get rid of parentheses

6x^2-4x^2+5x-6x+10=0

We add all the numbers together, and all the variables

2x^2-1x+10=0

a = 2; b = -1; c = +10;
Δ = b2-4ac
Δ = -12-4·2·10
Δ = -79
Delta is less than zero, so there is no solution for the equation

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